stpcpy - copy a string returning a pointer to its end
#include <string.h>
char *stpcpy(char *dest, const char *src);
The stpcpy() function copies the string pointed to by src (including
the terminating `\0' character) to the array pointed to by dest. The
strings may not overlap, and the destination string dest must be large
enough to receive the copy.
stpcpy() returns a pointer to the end of the string dest (that is, the
address of the terminating null character) rather than the beginning.
For example, this program uses stpcpy to concatenate foo and bar to
produce foobar, which it then prints.
#include <string.h>
int
main (void)
{
char *to = buffer;
to = stpcpy (to, "foo");
to = stpcpy (to, "bar");
printf ("%s\n", buffer);
}
This function is not part of the ANSI or POSIX standards, and is not
customary on Unix systems, but is not a GNU invention either. Perhaps
it comes from MS-DOS.
strcpy(3), bcopy(3), memccpy(3), memcpy(3), memmove(3)
GNU 1995-09-03 STPCPY(3)
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